61A - Ultra-Fast Mathematician - CodeForces Solution


implementation *800

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Python Code:

a=input()
b=input()
l=[]
for i in range(len(a)):
    if(a[i]==b[i]):
        l.append(0)
    else:
        l.append(1)
print(*l,sep='')

C++ Code:

#include <bits/stdc++.h>
using namespace std;
int main(){
     cin.tie(0);
    string ch1, ch2;
    cin>>ch1>>ch2;
    int n;
    n=sizeof(ch1);
    for (size_t i=0 ;i<ch1.size();i++)
    if (ch1[i]==ch2[i]){
        ch1[i]='0';
    }
    else {
        ch1[i]='1';
    }
    cout<<ch1;
    return 0;
                         }


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